The order and degree of the differential equation (1 + 3dy/dx)^(2/3) = 4d^3y/dx^3 are
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Answer:
The answer is as follows:
Step-by-step explanation:
The given differential equation can be rewritten as :
(1+3dy/dx)^2=4(d^3y/dx3)^3
From here we can easily get the order and degree of given equation which are 3 and 3, respectively.
Thank you.
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