Question

The order and degree of the differential equation d2ydx2 + (dydx)14 + x13 = 0 respectvely, are​

Answer 1

Answer:

Given that,

dx

2

d

2

y

+(

dx

dy

)

4

1

=−x

5

1

⇒(

dx

dy

)

1/4

=−(x

1/5

+

dx

2

d

2

y

)

On squaring both sides, we get

⇒(

dx

dy

)

2

1

=

⎝

⎛

x

5

1

+

dx

2

d

2

y

⎠

⎞

2

Again, on squaring both sides, we have

dx

dy

=(x

1/5

+

dx

2

d

2

y

)

4

order =2, degree does not defined when we expand

⎝

⎛

x

5

1

+

dx

2

d

2

y

⎠

⎞

4

it cannot be in polynomial expansion.