the order of reaction with respect to A and B are
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A + B -- > product
the rate of the reaction is given as
R = k [ A ]^n [ B ] ^ m
here ,
- R = rate of the reaction
- k = rate constant
- [ A ] and [ B ] = conc of the reactant
Let the order of [ A ] and [ B ] be n and m respectively
we need to find the values of m and n
As per the question ,
the rate of the reaction was doubled when concentration of a was doubled
R ' = k [2 A ]^n [ B ] ^ m
R ' = 2 k [ A ]^n [ B ] ^ m
Now substituting k [ A ]^n [ B ] ^ m as R ,
R ' = 2 R
this means that the order of A must be 1
Therefore , n = 1
Now ,
the again the rate of the reaction was doubled when the concentrations of A and B both were doubled
R " = k [2 A ]¹ [ 2 B ] ^ m
from this we can conclude that the order of B must be zero
m = 0
R " = k [ 2 A ]¹ [2 B ] ^0
R " = k [ 2 A ]¹ × 1
R " = 2 R
ANSWER :
- n = 1 ,m = 0
- R = k [ A ]^1 [ B ] ^0
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