The order of reactivity of alkyl halides towards elimination reaction is a) 3>2>1 b)2>1>3 c)3>1>2 d)1>2>3
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The reactivity of the alkyl halide is decided by the ease with which the halide leaves the substrate. As per the leaving ability, the order is I>Br>Cl>F.
We know that t-butyl bromide is not expected to react by an SN2 mechanism. Furthermore, the ethanol solvent is not sufficiently polar to facilitate an SN1 reaction. The other reactant, cyanide anion, is a good nucleophile; and it is also a decent base, being about ten times weaker than bicarbonate. Consequently, a base-induced elimination seems to be the only plausible reaction remaining for this combination of reactants. To get a clearer picture of the interplay of these factors consider the reaction of a 2º-alkyl halide, isopropyl bromide, with two different nucleophiles.