The order of the oxidation state of the phosphorus atom in H₃PO₂, H₃PO₄, H₃PO₃ and H₄P₂O₆ is
(A) H₃PO₃ > H₃PO₂ > H₃PO₄ > H₄P₂O₆
(B) H₃PO₄ > H₃PO₂ > H₃PO₃ > H₄P₂O₆
(C) H₃PO₄ > H₄P₂O₆ > H₃PO₃ > H₃PO₂
(D) H₃PO₂ > H₃PO₃ > H₄P₂O₆ > H₃PO₄
Answers
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H₃PO₃ > H₃PO₂ > H₃PO₄ > H₄P₂O₆ is the correct answer (A)
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Explanation:
C}. Oᴘᴛɪᴏɴ
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