the organic compound containing carbon .hydrogen and oxygen having molecular mass 46 their percentage composition in the compond is 52. 13 &35 respectivly calculate the molecular formula of compond
Answers
Answer:
The molecular formula of the organic compound is C₄H₁₈O.
Explanation:
To determine the molecular formula of the organic compound containing carbon, hydrogen, and oxygen with a molecular mass of 46 and percentage composition of 52% carbon, 13% hydrogen, and 35% oxygen, we can follow the following steps:
Step 1: Calculate the empirical formula
The empirical formula of a compound gives the simplest whole number ratio of atoms of each element present in the compound.
To calculate the empirical formula, we can assume a 100-gram sample of the compound and convert the percentage composition to grams. Then, we can divide each element's mass by its atomic mass and determine the simplest whole number ratio.
Mass of carbon = 52g
Mass of hydrogen = 13g
Mass of oxygen = 35g
Number of moles of carbon = 52g / 12.01 g/mol = 4.33
Number of moles of hydrogen = 13g / 1.01 g/mol = 12.87
Number of moles of oxygen = 35g / 16.00 g/mol = 2.19
Dividing each number of moles by the smallest number of moles, we get:
C: 4.33 / 2.19 = 1.98
H: 12.87 / 2.19 = 5.88
O: 2.19 / 2.19 = 1
Multiplying each by a common factor to obtain whole numbers, we get:
C: 2
H: 9
O: 1
Therefore, the empirical formula of the compound is C₂H₉O.
Step 2: Calculate the molecular formula
The molecular formula gives the actual number of atoms of each element present in the compound. To calculate the molecular formula, we need to know the molecular mass of the compound.
The empirical formula mass of C₂H₉O is:
= 2(12.01 g/mol) + 9(1.01 g/mol) + 1(16.00 g/mol)
= 46.12 g/mol
To find the molecular formula, we need to divide the molecular mass (46 g/mol) by the empirical formula mass (46.12 g/mol) and multiply the subscripts in the empirical formula by this factor:
Molecular formula = empirical formula x (molecular mass / empirical formula mass)
Molecular formula = C₂H₉O x (46 g/mol / 46.12 g/mol)
Molecular formula = C₂H₉O x 0.9974
Molecular formula = C₄H₁₈O
Therefore, the molecular formula of the organic compound is C₄H₁₈O.
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