Question

The organisers of an essay compelition decide that a winner in ​the competition

Answer 1

Given, Total number participants = 63

Total prize money distributed =

Rs 3000Winner gets a prize of Rs 100

Who does not win gets a prize of Rs 25

Number of winners = ?

Let the number of winners = m

Since,Number of winners + Number of losers = Total number of participants

Or, m + Number of losers = 63

By transposing ‘m’ to RHS, we getNumber of losers = 63 – m

Now,Total Prize money distributed to winners=

Number of winners X prize money distributed to each winner = m X 100 = 100m

Total prize money distributed to losers

= Number of losers X prize money distributed to each loser= (63 – m) X 25 = (63 x 25) – 25 m = 1575 – 25 m

Now,Total Prize money of winners + Total Prize money of losers =

Total prize money

By substituting the total prize money distributed to winners and total prize money distributed to losers, we get100 m + 1575 – 25 m = 3000

⇒ 100 m – 25 m + 1575 = 3000By transposing 1575 to RHS, we get100 m – 25 m = 3000 – 1575⇒75 m = 1425

After dividing both sides by 75, we get the answer.

Thus, number of winners = 19 Answer

Answer 2

Answer:

This will be the equation formed in tis question ---

100x (63 - x) 25x = 3000

25 will be divided by 100 and 3000... So 100x will become 4x

4x (63 - x) = 3000/25

After opening the bracket, variables one side -- so --

3x + 63 = 120

3x = 120 - 63

     = 57

3x = 57

x    = 57/ 3

     = 19

Answer = There are 19 winners

Hope this helps you

Please mark as brainliest