Math, asked by alishamohant, 8 months ago

The organisers of an essay competition decided that a winner in the competition gets a prize of rs 100 and a participant who does not win gets a prize of rs 25 . the total prize money distributed is rs3000 . find the number of winners , lf the total number of participants is 63 .​

Answers

Answered by ananyagn2005
2

Answer:

Let x be the number of the winners. So, the number of participants who does not win (63−x).

Prize money given to x winners = Rs. (100×x)= Rs. 100x

and prize money given to (63−x) participants = Rs. 25(63−x)

Given, total prize money distributed = Rs. 3000

∴100x+25(63−x)=3000

⇒4x+(63−x)=120 ...[On dividing both sides by 25]

⇒3x+63=120

⇒3x=120−63 ...[Transposing 63 to RHS]

⇒3x−57⇒x=

3

57

=19

∴ The number of winners is 19.

Answered by sha2nk5667905134
0

Given,

winner gets a prize =100 Rs

Who doesn't get = 25 Rs

Total Prize money = 3000 Rs

Total no of participants = 63

To find,

Number of winners = ??

Solution,

Let,

No of winner = x

no of participants who doesn't win = (63-x)

now,

Prize money got by Winner participants

= 100x Rs

Prize money got by those who doesn't win

= 25(63-x) Rs

Given,

Total prize money = 3000 Rs

prize money(who win) + prize money (who

doesn't win) = 3000 Rs

100x + 25 (63-x) = 3000

100x + 25×63 - 25x = 3000

100x-25x = 3000 - 25×63

75x = 3000 - 1575

75x = 1425

x = 1425/75 = 19

hence,

Number of winners = x = 19

hope this is useful for you.

plz mark my answer as brainliest.

follow me.

Attachments:
Similar questions