Math, asked by promixcoolarmy, 10 months ago

The organized list below shows all possible outcomes when four fair coins are flipped.
Each coin lands facing either heads up (H) or tails up (T).

HHHH HHHT HTHH HHTT HHTH HTHT HTTH HTTT

TTTT TTTH THTT TTHH TTHT THTH THHT THHH

What is the probability that at least three coins land facing tails up? Give the probability as a percent.
Enter your answer in the box.
P(at least three tails) =

Answers

Answered by amitnrw
10

Given : all possible outcomes when four fair coins are flipped.

To find : probability that at least three coins land facing tails up

Solution:

Sample Space

= { HHHH ,  HHHT, HTHH , HHTT , HHTH , HTHT , HTTH , HTTT , TTTT , TTTH ,THTT, TTHH ,TTHT ,THTH, THHT ,THHH}

n(S) = 16

at least three coins land facing tails up = 3 Tails  up + 4 Tailsup

E = { HTTT , TTTT , TTTH ,THTT,  TTHT    }

n(E)  = 5

Probability (at least three tails) = n(E)/n(S)  =  5/16

probability  = 3 Tail  + 4 Tails

= ⁴C₃(1/2)(1/2)³  + ⁴C₄(1/2)⁰(1/2)⁴

= 4 (1/16) + 1/16

= 5/16

probability that at least three coins land facing tails up = 5/16

P(at least three tails) =   5/16

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Answered by victoriajanton4
3

Answer:

5\12

Step-by-step explanation:

my teacher did it for me

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