Math, asked by ramrenuria, 8 months ago

the origin O, B(-6,9) and C(12,-3) are vertices of triangle OBC. Point P divides OB in the ratio 1:2 and point Q divides OC in the ratio 1:2. find the coordinates of points P and Q. Also, show that PQ=1/3BC​

Answers

Answered by jefferson7
14

the origin O, B(-6,9) and C(12,-3) are vertices of triangle OBC. Point P divides OB in the ratio 1:2 and point Q divides OC in the ratio 1:2. find the coordinates of points P and Q. Also, show that PQ=1/3BC​

Step-by-step explanation:

We are given P that divides OB IN THE RATIO 1:2 and point Q divides OC in the ratio 1:2

Using the section formula the coordinates of P are

(-6 +0 )/3   (9+0)/3 = (-2,3)

(12+0)/3 ( -3+0)/3   = (4,-1)

Therefore the coordinates of P and Q are (-2,3) and (4,-1)

For the first point

= √(-6 -12)² + √(9+3)²

=√324+√144

=√468

For the second point

= √(4+2)² + √(-1-3)²

=√36+√36

=√52

√468 = √9*52

=3√52

=3BC

Answered by lbalarajulbalaraju2
4

Answer:

yes its not understand plase send the answer

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