Question

the origin shifted to the point O' (2,2) the axis remaining in the same direction, find the new equation of the locus , y^-4x-4y+12=O.​

Answer 1

Step-by-step explanation:

given equation is , y-4x-4y+12=0

if the loci is shifted to O'(2,2)

then x= X'+2 ; y=Y'+2

then the equation become

(Y'+2)-4(X'+2)-4(Y'+2)+12=0

=>Y'+2-4X'-8-4Y'-8+12=0

=> Y'+2+4X'=0