the original length of a metal is 1 meter and the final lenght of the metal is 1.02 meter. the change in temparature is 50 kelvin. find the coefficient of linear expansion??
Answers
Explanation:
. A steel is 40 cm long at 20 oC. The coefficient of linear expansion for steel is 12 x 10-6 (Co)-1. The increase in length and the final length when it is at 70 oC will be…
Known :
The change in temperature (ΔT) = 70oC – 20oC = 50oC
The original length (L1) = 40 cm
Coefficient of linear expansion for steel (α) = 12 x 10-6 (Co)-1
Wanted : The change in length (ΔL) and the final length (L2)
Solution :
a) The change in length (ΔL)
ΔL = α L1 ΔT
ΔL = (12×10-6 oC-1)(40 cm)(50oC)
ΔL = (10-6)(24 x 103) cm
ΔL = 24 x 10-3 cm
ΔL = 24 / 103 cm
ΔL = 24 / 1000 cm
ΔL = 0.024 cm
b) The final length (L2)
L2 = L1 + ΔL
L2 = 40 cm + 0.024 cm
L2 = 40.024 cm
Answer:
. The original length of metal is 1 meter and the final length is 1.02 m. The change in temperature is 50 Kelvin. Determine the coefficient of linear expansion!
Known :
The initial length (L1) = 1 meter
The final length (L2) = 1.02 meter
The change in length (ΔL) = L2 – L1 = 1.02 meter – 1 meter = 0.02 meter
The change in temperature (ΔT) = 50 Kelvin = 50oC
Wanted : The coefficient of linear expansion
Solution :
ΔL = α L1 ΔT
0.02 m = α (1 m)(50oC)
0.02 = α (50oC)
α = 0.02 / 50oC
α = 0.0004 oC-1
α = 4 x 10-4 oC-1