Question

the original price of ana article was $3,000.if ricky got successive discounts of 15%and 25% yhen howmuch did he pay to buy articles​

Answer 1

➤ Correct Question :-

The cost price of an article was ₹3000. If Ricky got successive discounts of 15% and 25%. Then, how much did he pay to buy the article?

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➤ Given :-

Cost price of an article :- ₹3000

First discount obtained :- 15%

Second discount obtained :- 25%

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➤ To Find :-

The cost paid by Ricky to buy the article

(selling price)

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★ How to do:-

Here, we are given with the cost price and the two successive discounts obtained to him while buying that article. We are asked to find the selling price or the cost given by him. So, first we should find the selling price of first discount. Then, we can find the new selling price by using second discount and first selling price. The suitable formulas are given while solving the problem. So, lets solve!!

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➤ Solution :-

Selling price on first discount :-

${\sf \leadsto \underline{\boxed{\sf \dfrac{(100 - Discount \bf\%)}{100} \times CP}}}$

Substitute the given values.

${\tt \leadsto \dfrac{100 - 15}{100} \times 3000}$

Subtract the values in numerator and write the fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{85}{100} \times 3000 = \dfrac{17}{20} \times 3000}$

Multiply the remaining numbers.

${\tt \leadsto \dfrac{17 \times 3000}{20} = \dfrac{51000}{20}}$

Write the fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{51000}{20} = 2550}$

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Now, let's find the final answer i.e, the selling price.

Selling price on second discount :-

${\sf \leadsto \underline{\boxed{\sf \dfrac{(100 - Discount \bf\%)}{100} \times CP}}}$

Substitute the given values.

${\tt \leadsto \dfrac{100 - 25}{100} \times 2550}$

Subtract the values in numerator and write the fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{75}{100} \times 2550 = \dfrac{3}{4} \times 2550}$

Multiply the remaining numbers.

${\tt \leadsto \dfrac{3 \times 2550}{4} = \dfrac{7650}{4}}$

Write the fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{7650}{4} = \pink{\underline{\boxed{\tt Rs \: \: 1912.5}}}}$

$\Huge\therefore$ Ricky has to pay ₹1912.5 to buy the article.

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$\dashrightarrow$ Some related formulas :-

$\begin{gathered} \small \boxed{\begin{array} {cc} \large \dag \: \sf More \: Formulas \\ \\ \sf \bigstar \: Profit = SP - CP \\ \\ \sf \bigstar \: Loss \: = CP - SP \\ \\ \sf \bigstar \: Profit \: percent = \dfrac{Profit}{Cost \: price} \times 100 \\ \\ \sf \bigstar \: Loss \: percent = \dfrac{Loss}{Cost \: price} \times 100 \\ \\ \sf \bigstar \: Cost \: price = \dfrac{100}{(100 + profit\%)} \times sp \\ \\ \sf \bigstar \: Selling \: price = \dfrac{(100 + profit\%)}{100} \times CP \\ \\ \sf \bigstar \: Cost \: price = \dfrac{100}{(100 - loss\%)} \times 100 \end{array}} \end{gathered}$

Answer 2

Answer:

Step-by-step explanation: