The orthocenter of the triangle formed by the lines 4x - 7y + 10 = 0, x + y = 5,
7x + 4y - 15 = 0 is
1) (1, 2)
2) (1, -2)
3) (-1, 2)
4) (-1, -2)
Answers
Answered by
2
here is your answer hope it's helpful
Attachments:

Answered by
1
Answer:(1,2)
Step-by-step explanation:Orthocentre is the intersection of any two of three altitude
line 4x-7y+10=0
7x+4y-15=0 ,point (1,2) satisfies these lines
Similar questions