The orthocenter of the triangle formed
by the points (1,0), ( - 1,0) and and
(0, 3) is
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Answer:
Step-by-step explanation:
Given a ΔOAB, which is a right-angled triangle at vertex O.
Also in right-angled triangle the orthocentre lies on the vertex which forms right angle.
So the orthocentre of ΔOAB is (0,0).
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