Question

the orthocentre O of Triangle ABC is interior of Triangle ABC. If OB=AC and AD=10 cm where AD is an altitude then AB is equal to
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Answer 1

Answer : 10sqrt(2)

Step-by-step explanation:

OB=AC cotB

and OB =AC( given)

therefore, cotB=1

B=45°

In triangle, ABD

sin45°=AD/AB and AD=10 (given)

AB=10sqrt(2)