Question

The orthocentre O of Triangle ABC is interior of Triangle ABC. If OB = AC and AD = 15 cm, where AD is an altitude, then AB equals​

Answer 1

Answer:

In tringle ABD & ACD

AB=AC (GIVEN)

ANGLE ADB=ANGLE ADC(BOTH ARE RIGHT ANGLES)

AD=AD(COMMON) 

SO BOTH THE TRIANGLES ARE CONGRUENT 

THEREFORE BD=CD(CPCT)

ANGLE BAD=ANGLE CAD(CPCT)

HENCE AD BISECTS BOTH BC AND ANGLE A