the orthocentre of ∆ ABCwhere vertices are A(-1,7),B(1,7),c(5,-5)
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Answer:
Centre of triangle is (5/3,3)
Step-by-step explanation:
To find the centre of triangle we have a formula
x = (x1 + x2 + x3 /3)
= -1 + 1 + 5/3
X = 5/3
y = (y1 + y2 + y3 /3)
y = 7 + 7 +(-5) /3
y = 14-5/3
y = 3
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