The orthocentre of the triangle formed by (0,0), (8,0) and (4,6) is
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(10/9,19/6) it is the coordinates of orthocentre
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Answer:
Consider a triangle ABC with coordinates A(0,0), B(4,6) and C (8,0) respectively.
From point A make a line AD perpendicular to BC and from point C make a line CE perpendicular to AB. Mark their point of intersection as O(orthocentre).
Now,
mBC =0-6/8-4=-3/4
mBC ×mAD=-1
mAD=-1/mBC
mAD=2/3
By two point formula
y-0=2/3(x-0)
y=2x/3...........(1)
mAB=6-0/4-0
mAB=3/2
mAB×mCE=-1
mCE=-1/mAB
mCE=-2/3
By two point formula
y-0=-2/3(x-8)
y=-2x/3 +16/3
Put value of y from equation (1)
2x/3=-2x/3+16/3
x=4
Putting value of x in equation (1),we get
y=2(4)/3
y=8/3
So the coordinates of orthocentre are O(4,8/3)
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