Question

The orthocentre of the triangle formed by the points
(1, 3), (2, 4) and (2, 3) is
(1) (1,3)
(2) (2, 4)
(3) (2, 3)
(4) (0, 0)​

Answer 1

Answer:

Answer=>(4) (0,0)

Step-by-step explanation:

Hope this helps you.

Answer 2

Answer:

3) (2,3)

Step-by-step explanation:

mAB = 1 (slope of AB)

mBC = 1/0

m of perpendicular of BC = 0

m of perpendicular of AC = -1

eq of perp of AB = y + x = 5

eq of perp of AC = y = 3

intersection of the 2 perpendiculars will give the orthocentre

equating the perpendiculars

x = 2

y = 3