The orthogonal projection of a¯=2i+3j+3k on b¯=i−2j+k is
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Given: a(bar) =2i + 3j + 3k on b(bar) = i − 2j + k
To find: Orthogonal projection of a on b?
Solution:
- Orthogonal projection: It is a two-dimensional graphic representation of an object in which the projecting lines are at right angles to the plane of the projection.
- Now we know the formula for orthogonal projection, that is:
- Orthogonal projection of a on b = a.b / mod(b)² x b(vector)
( 2i + 3j + 3k . i − 2j + k / 1+4+1 ) x i − 2j + k
( 2 - 6 + 3 / 6 ) x i − 2j + k
-1/6 x i − 2j + k
-i +2j -k / 6
Answer:
Orthogonal projection of a on b is -i +2j -k / 6
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