Question

The osmotic pressure of 0.2 M KCl solution at 310 K is​

Answer 1

Answer:

osmotic pressure = CRT

osmotic pressure = 0.2 X 8.314 X 310

osmotic pressure = 515.468 units

Answer 2

The osmotic pressure of the solution is 10.18 atm.

Explanation:

To calculate the osmotic pressure, we use the equation:

$\pi=iMRT$

where,

$\pi$ = osmotic pressure of the solution

i = Van't hoff factor = 2   (for KCl)

M = molarity of KCl = 0.2 M

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = 310 K

Putting values in above equation, we get:

$\pi=2\times 0.2\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 310K\\\\\pi=10.18atm$

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