Question

the osmotic pressure of 1kg solution containing 50g of glucose at 300 k is​

Answer 1

Explanation:

Osmotic pressure is proportional to the molarity, C, of the solution at a given temperature T. Thus

π=CRT ...(i)

Where,

π= osmotic pressure

R= gas constant =0.0821dm

3

atm mol

−1

K

−1

T= temperature =298K

C= molarity =

V

n

=

M×V

w

...(ii)

Where,

n= no. of moles

w= Weight of solute glucose =4.5g

M= Molecular weight of solute glucose =180g

V= Volume of solution =100ml=0.1L

Putting the values in the formula (i) and (ii) we get :

π=

MV

wRT

=

180×0.1

4.5×0.0821×298

=

18

110.09

=6.12atm

The osmotic pressure of the solution is 6.12atm.