Question

the osmotic pressure of 1kg solution containing 50g of glucose at 300 k is​

Answer 1

Answer:

O.P = C x R x T , where C is the concentration , R is Universal Gas Constant and T is temperature ...

C=(moles of solute)/(volume of solution)

C=(wt/molar mass) / (mass of sol^n X density of sol^n)

C=(50/180) / (1000 x 1.02)

C=0.00027

O.P= 0.00027 x 8.314 x 300

O.P=0.67924

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