Question

The osmotic pressure of 1M solution at 27°c is? ( please give answer) ​

Answer 1

                      ░▒▓█►─═ ʜᴇʀᴇ ɪs ʏᴏᴜʀ ᴀɴsᴡᴇʀ ═─◄█▓▒░

Answer:- The osmotic pressure of 1 M solution at 27oC is 24.6 atm.

Proof:-

∏ = CRT

  = 1 × 0.082 × 300

 = 24.6 atm

ʙᴇ ʏᴏᴜʀs.........^_^

Answer 2

The question is incomplete, here is the complete question:

The osmotic pressure of 1 M glucose solution at 27°C is

The osmotic pressure of the solution is 24.63 atm.

Explanation:

To calculate the osmotic pressure, we use the equation:

$\pi=iMRT$

where,

$\pi$ = osmotic pressure of the solution

i = Van't hoff factor = 1  (for non-electrolytes)

M = molarity of glucose = 1 M

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $27^oC=[273+27]=300K$

Putting values in above equation, we get:

$\pi=1\times 1\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 300K\\\\\pi=24.63atm$

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