Question

The osmotic pressure of a 5 percent solution of a
non volatile solute is 5.07 atm at 150℃
Calculate the molar mass of the solute​

Answer 1

Answer:

I am assuming percentage given as (mass/ volume), since you must specify.

We are given with a 5% non volatile solute. Which means, 5g solute in 100 ml of a solution.

If 100ml has 5g solute,

then, 1000ml should have 50 g solute.

(I used some unitary method here.)

We know, $\pi =CRT$

so, let's put R= 0.082 $L-atm -K^{-1} mol^{-1}$ and T= 423K.

We arrive at, Concentration, C= 0.146M

Now, since we had already worked on the framework,

$\frac{mol}{volume}$ = 0.146

So, moles comes to be 0.146, if we take 1L or 1000ml.

$\frac{50}{m}$ = 0.146

comes out to be, m= 342g.