the Osmotic pressure of an aqueous solution of protein containing 0.63 gram of protein in hundred gram of water at 300 Kelvin was found to be 0.00026 ATM. calculate the molar mass of protein.
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Answer:
61038 g mol
−1
πv=
m
w
RT
2.57×10
−3
×
1000
200
=
m
1.26
×0.083×300
m=61038 gm mol
−1
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