Chemistry, asked by shashisathwik717, 8 months ago

The osmotic pressures of 0.01 M solutions of KI and of sucrose are 0.432 atm and 0.24 atm respectively at same temperature. The Van’t Hoff factor for KI is …..

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Answered by akanshaagrwal23
5

Answer:

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Answered by Jasleen0599
0

GIven:

The molarity of KI and sucrose both, C = 0.01 M

The osmotic pressure of KI solution, Π(KI) = 0.432 atm

The osmotic pressure of sucrose solution, Π(sucrose) = 0.24 atm

To Find:

The Van’t Hoff factor for KI.

Calculation:

- As sucrose does not dissociate in water, the osmotic pressure of sucrose: Π(sucrose) = C × R × T

⇒ 0.24 = 0.1 × R × T

⇒ R × T = 2.4 ....(i)

- As KI dissociates in water, the osmotic pressure of KI:

Π(KI) = i × C × R × T

⇒ 0.432 = i × 0.1 × 2.4     {from (i)}

⇒ i = 0.432/0.24

i = 1.8

- So, the Van’t Hoff factor for KI is 1.8

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