The osmotic pressures of 0.01 M solutions of KI and of sucrose are 0.432 atm and 0.24 atm respectively at same temperature. The Van’t Hoff factor for KI is …..
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The molarity of KI and sucrose both, C = 0.01 M
The osmotic pressure of KI solution, Π(KI) = 0.432 atm
The osmotic pressure of sucrose solution, Π(sucrose) = 0.24 atm
To Find:
The Van’t Hoff factor for KI.
Calculation:
- As sucrose does not dissociate in water, the osmotic pressure of sucrose: Π(sucrose) = C × R × T
⇒ 0.24 = 0.1 × R × T
⇒ R × T = 2.4 ....(i)
- As KI dissociates in water, the osmotic pressure of KI:
Π(KI) = i × C × R × T
⇒ 0.432 = i × 0.1 × 2.4 {from (i)}
⇒ i = 0.432/0.24
⇒ i = 1.8
- So, the Van’t Hoff factor for KI is 1.8
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