Question

the other number.
3. The HCF of two numbers is 7 and the product
of the numbers is 3430. Find the LCM of the
numbers.
4. The product of two numbers is 1152 and their
LCM is 288. Find their HCF.​

Answer 1

Answer:

3.LCM of two numbers is 490.

Solution:

HCF of two numbers = 7,

Product of two numbers = 3430,

So we use,

HCF * LCM = Product of two numbers.

LCM of two numbers = 3430/7,

Hence, LCM of two numbers is 490.

4.We know that:

Product of two numbers = Product of their H.C.F. and L.C.M.

=> 1st number x 2nd number = Product of their H.C.F. and L.C.M.

=> 48 x 2nd number = 1152

=> 2nd number = \frac { 1152 }{ 48 } = 24

Answer 2

Answer:

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