Question

the other two 546 Tind the numbers
013 Three consecutive natural numbers are such that the sum of the square of middle term exceeds the
difference of the squares of the other two by 69 find the number

Answer 1

Answer:

Let the number be x−1,x.x+1

Given

x2−[(x+1)2−(x−1)2]=60

x2−[(x+1)2−(x−1)2]+60

x2=4x+60

⇒ x2−4x−60=0

⇒ x2−10x+6x−60=0

x(x−10)+6(x−10)=0

(x+6)(x−10)=0

⇒ x=6,10

∴  The numbers are 9,10,11