Question

the outer and inner diameter of a circular ring are 34 cm and 32 cm respectively. The area of the ring is

Answer 1

Answer:

$Area \:of \: the \:ring (A)= 33\pi \:cm^{2}$

Step-by-step explanation:

Let the Outer diameter of the ring (D) = 34 cm,

Inner diameter of the ring (d) = 32 cm,

$Area \:of \: the \:ring (A)\\ = \frac{\pi D^{2}}{4}-\frac{\pi d^{2}}{4}\\=\frac{\pi}{4}\left(D^{2}-d^{2}\right)$

$=\frac{\pi}{4}\left(34^{2}-32^{2}\right)\\=\frac{\pi}{4}\left(D+d\right)\left(D-d\right)\\=\frac{\pi}{4}\left(34+32\right)\left(34-32\right)\\=</p><p>\frac{\pi}{4}\times 66\times 2=\frac{33\pi}\:cm^{2}$

Therefore,

$Area \:of \: the \:ring (A)= 33\pi \:cm^{2}$

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Answer 2

Step-by-step explanation:

\begin{gathered}=\frac{\pi}{4}(34^{2}-32^{2})\\=\frac{\pi}{4}(D+d)(D-d)\\=\frac{\pi}{4}(34+32)(34-32)\\= \frac{\pi}{4}\times 66\times 2=\frac{33\pi}\:cm^{2}\end{gathered