Question

The outer circumference of a circular track is 194.68 m and the track is everywhere 6 m wide. find the cost of levelling the track at the rate of 25 paise per m^2 . [Take π = 3.14]​

Answer 1

Answer:

Let the radius of outer circle be R

Given: Circumference of outer circle = 194.68 m

⇒ 2πR = 194.68 m

⇒ 2 × 3.14 R = 194.68 m

=>R=31m

⇒ Radius of inner circle (r) = Radius of outer circle – width

= 31 m – 6 m = 25 m

Thus area of track = area of outer circle – Area of inner circle

= πR²– πr² = π (R²- r²)=1056m²

Now cost of leveling 1 m2 = 25 paise = Rs 0.25

Hence cost of leveling track = Rs 0.25 × 1056 = Rs 264

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