Question

The outer diameter of a cylindrical wooden pipe is 30cm and its inner diameter is 26cm. The

length of the pipe is 42cm. Find the mass of the pipe if 1cm3

of wood has a mass of 0.8g.​

Answer 1

Answer:

volume = 4/3 π R3 - 4/3π r3

where R is the outer radius and r is the inner radius

4/3*22/7* (15^3- 13^3)

=4936.4cm^3

density= 0.8g/cc

mass= density* volume

= 0.8*4936.4

=3949.12g