The outer diameter of a gas cylinder is 20 centimeters. Find the cost of painting of its outer curved surface at ₹4 per square centimeter if the height of the cylinder is 70 centimeter.
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16
Outer radius, r = 20/2 = 10 cm
Height, h = 70 cm
![curved \: surface \: area = 2\pi \: rh \\ = 2 \times \frac{22}{7} \times 10 \times 70 = 4400 \: {cm}^{2} \\ \\ cost \: of \: painting = 4400 \times 4 \\ = Rs. \: 17600 curved \: surface \: area = 2\pi \: rh \\ = 2 \times \frac{22}{7} \times 10 \times 70 = 4400 \: {cm}^{2} \\ \\ cost \: of \: painting = 4400 \times 4 \\ = Rs. \: 17600](https://tex.z-dn.net/?f=curved+%5C%3A+surface+%5C%3A+area+%3D+2%5Cpi+%5C%3A+rh+%5C%5C++%3D+2+%5Ctimes++%5Cfrac%7B22%7D%7B7%7D++%5Ctimes+10+%5Ctimes+70+%3D+4400+%5C%3A++%7Bcm%7D%5E%7B2%7D++%5C%5C++%5C%5C+cost+%5C%3A+of+%5C%3A+painting+%3D+4400+%5Ctimes+4++%5C%5C++%3D+Rs.+%5C%3A+17600)
Height, h = 70 cm
Answered by
5
as you know
the lateral (or curved) surface area of a cylinder = 2πrh
=2π10* 70
=1400*22/7
=4400*4
=17600
thus, the cost of painting its outer curved surface at Rs. 4 is rs.17600
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