The outer diameter of a gas cylinder is 20 cm. Find the cost of painting of its outer curved surface at ₹ 4 per cm square if the height of the cylinder is 70 cm square.
Answers
Answer:
Given,Outer diameter = 20cm
Therefore,Radius,r=20cm/2=10cm
Height,h=70cm
Therefore,CSA=2×22/7×10×70
=4400cm square
Therefore,cost of painting its outer curved surface at ₹ 4 per cm square=4400cm square ×4
=17600cm square.
Step-by-step explanation:
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What we have to do ?
We are given the outer diameter of a gas cylinder is 20 cm and it's height is 70 cm² respectively. Cost of painting per cm² is ₹ 4. For finding total cost first we will find radius then curved surface area and therefore simply multiplying it with the per cm cost.Let's do it :-
Curved surface area of a Cylinder :-
Where :-
- r = Radius of the cylinder
- h = Height of the cylinder
According to the Question :
Have to find the radius of the base of the cylinder first.
We Know that ,
Given , Diameter = 20 cm.
Putting the value in the diameter , we get :
Hence the Radius of the Cylinder is 10 cm.
Finding CSA of cylinder :-
- Radius = 10 cm
- Height = 70 cm
The value of π is taken as 22/7 , if the value is not mentioned in the question.
Now , using the formula :-
Substituting the respective values, we get :
For Finding Total cost :-
Curved surface area × Per cm cost
- Curved surface area → 4400 cm²
- Per cm cost → 4 Rupees
Total cost = 4400 × 4
Total cost = 17600 Rupees
Hence,