The outer diameter of a hemispherical bowl made
of copper sheet 1 cm thikness is 10cm.
Find the
cost to polish the whole surface of the bowl at
the role of Rs 1.50 per sq. cm.
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Answer:
Inner radius=24.7cm
Thickness=0.3cm
Outer radius=(24.7+0.3)cm
=25cm
outer surface area of bowl=2πr
2
=2×3.14×25×25
=3925cm
2
cost of polishing 10cm
2
surface area=Rs.4
∴ cost of polishing 3925cm
2
surface area=
10
4×3925
=Rs.1570
solution
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