Math, asked by soumyadongare256, 4 months ago

The outer diameter of a long concrete pipe is 68 cm and its wall thickness is 4 cm. If the water flows at a rate of 9 litres per minute, how long (in m) would the water have flowed in an hour?

Answers

Answered by Anonymous
1

In the figure

MP = AP – AM = (12 – 4) cm = 8 cm

PD = AD – AP = (18 – 12) cm = 6 cm

NQ = AQ – AN = (14 – 8) cm = 6 cm

QD = AD – AQ = (18 – 14) cm = 4 cm

Area of the polygon ABCDEF

= area of ∆AFM + area of trapezium FMPE + area of ∆EPD

+ area of ∆ANB + area of trapezium NBCQ + area of

∆QCD.

= 1

2 × AM × FM +

1

2 (FM + EP) × MP +

1

2 PD × EP +

1

2 ×

AN × NB +

1

2 (NB + CQ) × NQ +

1

2 QD × CQ

= 1

2 × 4 × 5 +

1

2 (5 + 6) × 8 +

1

2 × 6 × 6 +

1

2 × 8 × 5 +

1

2

(5 + 4) × 6 +

1

2 × 4 × 4.

= 10 + 44 + 18 + 20 + 27 + 8 = 127 cm2

Answered by pk2000207
0

Step-by-step explanation:

The outer diameter of a long concrete pipe is 68 cm and its wall thickness is 4 cm. If the water flows at a rate of 9 litres per minute, how long (in m) would the water have flowed in an hour?

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