Question

The outer diameter of a metallic cylindrical tube is 14 cm and thickness of the tube is 1 cm. Find the weight of 2 m long tube if the density of metal is 7 gm/cm³

Answer 1

Inner radius,r=12/2=6cm

thickness=1cm

so,outer radius,R=6+1=7cm

height,h=1m=100cm

volume=pi×(R^2-r^2)×h

=22/7×(7^2-6^2)×100

=22/7×(49-36)×100

=22/7×13×100

286/7×100

=28600/7

since,density=7.7gm/cm^3

also,weight=volume×density

weight=28600/7×7.7gm

=31460gm

or,31.46 kg

Answer 2

Answer:

Step-by-step explanation:

Outer radius=7cm (R)

Inner Radius=6cm (r)

Volume of hollow cylinder = πh(R²-r²)

=(22/7)*200cm*(7²-6²)

=(22/7)*200*13

=57200/7 cm³

Weight=Density*Volume

=57200/7*7

=57200gm or 57.2 kg