the outer dimension of a jewellery box made of wood are 20 cm * 16 cm * 8 cm. The thickness of wood is 1 cm .Find the total cost of wood required to make the box if 1 cm cube of wood cost rupees 2.50. Answer is 2620
Answers
Answer:
2620 Rs
Step-by-step explanation:
Given:
Outer length = 20 cm
Outer width = 16 cm
Outer height = 8 cm
Therefore, outer volume = Length×Width×Height
= 20×16×8
= 2560
Since the thickness of the wooden box is 1 cm,
Inner length = 20 - 2(1) = 18 cm
Inner width = 16-2(1) = 14 cm
Inner height = 8-2(1) = 6 cm
Therefore, the inner volume = 18×14×6 = 1512
Therefore,
the volume of the wood used = Outer volume - Inner Volume = 2560-1512 = 1048
Since the cost of 1 = 2.5 Rs, therefore, the total cost = 2.5×1048 = 2620 Rs
The total cost of wood required is Rs. 2620
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Answer:
Outer length of box = 20 cm
Outer breadth of box = 16 cm
Outer height of box = 8 cm
The thickness of the wood is 1 cm .
So, Inner length of box = 20 -(1+1)=18 cm
Inner breadth of box = 16-(1+1)=14 cm
Inner height of box = 8-(1+1)=6 cm
Volume of wood used = Outer volume - Inner volume
Volume of wood used = (20 \times 16 \times 8)-(18 \times 14 \times 6)(20×16×8)−(18×14×6)
Volume of wood used =1048 cm^31048cm
3
Cost of 1 cubic cm = Rs.2.5
Cost of 1048 cubic cm = 1048 \times 2.5 = Rs.26201048×2.5=Rs.2620
Hence the total cost of wood required to make the box is Rs.2620