Chemistry, asked by Anonymous, 6 months ago

The outer electronic configuration of two elements is given as a) 3s^2 3p^4 b) 3d^10 4s^2. to which block of elements in the periodic table each of these belong?

Answers

Answered by AbhinavRocks10

Explanation:

The given configuration is 3s23p64s2. As the last electron enters the s orbital its a s block element.It belongs to the s block II A group. That is it belongs to the alkaline earth metal.As well as it belongs to the 4th period of the table.

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The outer electronic configuration of two elements is given as a) 3s^2 3p^4 b) 3d^10 4s^2. to which block of elements in the periodic table each of these belong?​

Answers

The outer electronic configuration of two elements is given as a) 3s^2 3p^4 b) 3d^10 4s^2. to which block of elements in the periodic table each of these belong?