the outer faces of a rectangular slab made of equal thickness of iron and brass are maintained at 100 degree C and 0 degree C respectively.the temperature at the interface is(thermal conductivity of iron and brass are 0.2 and 0.3 respectively)
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The temperature at the interface is 10°C.
Explanation:
If T is temperature of the interface of iron and brass slabs, then
dQ / dt = K1 . A(100 − T) / Δx = KB. A (T − 0) Δx
K1 (100 − T) = KBT
100 − T / T = KB / K1 =126 / 14 = 0
T = 10 °C
Hence the temperature at the interface is 10°C.
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