the outer length and breath of a painting is 150cm*120cm.if there is margin of 8cm width all around the painting.find the area of actual painting.
Answers
Answered by
136
Hi ,
The dimensions of the rectangular painting ,
Length = L = 150cm
Breadth = B = 120 cm
According to the problem,
The width of the marigin around the painting = w = 8 cm
Now , the diminsions of the actual painting are
Length of the actual painting = l = L - 2w
l = 150 - 2 × 8
l = 150 - 16
l = 134 cm
Breadth of the actual painting = b = B - 2 w
b = 120 - 2 × 8
b = 104 cm
Therefore,
Area of the actual painting = l × b
= 134 cm × 104 cm
= 13936 square cm
I hope this will useful to you.
*******
The dimensions of the rectangular painting ,
Length = L = 150cm
Breadth = B = 120 cm
According to the problem,
The width of the marigin around the painting = w = 8 cm
Now , the diminsions of the actual painting are
Length of the actual painting = l = L - 2w
l = 150 - 2 × 8
l = 150 - 16
l = 134 cm
Breadth of the actual painting = b = B - 2 w
b = 120 - 2 × 8
b = 104 cm
Therefore,
Area of the actual painting = l × b
= 134 cm × 104 cm
= 13936 square cm
I hope this will useful to you.
*******
Answered by
17
Answer:
Step-by-step explanation:
The dimensions of the rectangular painting ,
Length = L = 150cm
Breadth = B = 120 cm
According to the problem,
The width of the marigin around the painting = w = 8 cm
Now , the diminsions of the actual painting are
Length of the actual painting = l = L - 2w
l = 150 - 2 × 8
l = 150 - 16
l = 134 cm
Breadth of the actual painting = b = B - 2 w
b = 120 - 2 × 8
b = 104 cm
Therefore,
Area of the actual painting = l × b
= 134 cm × 104 cm
= 13936 square cm
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