Question

the outer radius and inner radius of a 30 cm long cylindrical gold pipe are 14 cm and 7 cm respectively it is filled with bronze densitions of gold and bronze at 20 gram per centimetre cube and 30 gram per centimetre cube respectively find the weight of the cylinder form.

Answer 1

Answer:

230790 gm

Step-by-step explanation:

Volume of cylinder = pie x r² x h

= 3.14 x 7² x 30 = 4615.8 cm³

Gold 20 gm / cm³

So,

4615.8 x 20 = 92316 gm

Bronze 30 gm/ cm³

So,

4615.8 x 30 = 138474 gm

Total weight = 92316 + 138474

= 230790 gm or 230.790 kg.

Answer 2

Given:

Height = 30cm,

Outer radius = 14cm and Inner radius = 7cm.

Density of gold = 20gm/cm³.

Density of bronze = 30gm/cm³.

To Find:

The weight of the cylinder.

Solution:

 We know that,

Volume of cylinder = π x r² x h.

Volume of cylinder = 3.14 x 7² x 30.

Volume of cylinder = 4615.8 cm³.

We have,

Gold density = 20 gm / cm³.

So,

Weight of gold = 4615.8 x 20 = 92316 gm.

And,

Bronze density = 30 gm/ cm³

So,

Weight of bronze = 4615.8 x 30 = 138474 gm.

Now, for total weight,

Total weight of the cylinder = 92316 + 138474

Total weight of the cylinder = 230790 gm.

Hence, the weight of the cylinder is 230790gm.