Question

The outer radius of a 3.5 metre long iron pipe is 3 cm and the inner radius is 2 CM if the weight of 1 cm ³ of iron is 2.5 gram find the weight of the iron pipe.​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Weight\:of\:pipe=13750gm=13.75\:kg}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given : }} \\ : \implies \text{Length = 3.5 \: m} \\ \\ : \implies \text{Outer \: radius}(r_{1}) = 3 \: cm \\ \\ : \implies \text{Inner \: radius}(r_{2}) = 2 \: cm \\ \\ : \implies 1 {cm}^{3} = 2.5 \: gm\\ \\ \red{\underline \bold{To \: Find : }} \\ : \implies \text{Weight \: of \: pipe = ?}$

• According to given question :

$\bold{For \: volume \: of \: pipe : } \\ : \implies \text{Volume \: of \: cylindrical \: pipe =} \pi \: h( { r_{1} }^{2} - r_{2}^{2} ) \\ \\ : \implies Volume = \frac{22}{7} \times 350 \times ( {3}^{2} - {2}^{2} ) \\ \\ : \implies Volume = \frac{22}{7} \times 350 \times (9 - 4) \\ \\ : \implies Volume = 22 \times 50 \times 5 \\ \\ \green{ : \implies \text{Volume = 5500 \: } {cm}^{3} } \\ \\ \bold{For \: weight \: of \: pipe } \\ : \implies \text{Weight \: of \: pipe }= 5500 \times 2.5 \\ \\ \green{ : \implies \text{ \red{W}\blue{e}\green{i}\purple{g}\orange{h}\pink{t} \: of \: pipe = 13750} \: gm}$

Answer 2

Answer:

• weight of pipe = 13750 gm

Step-by-step explanation:

$\implies volume \: of \: pipe = \pi \: h( {r1}^{2} - {r2}^{2} ) \\ \\ \implies volume \: of \: pipe = \frac{22}{7} \times 350 \times ( {3}^{2} - {2}^{2} ) \\ \\ \implies volume = 22 \times 50 \times 5 \\ \\\implies volume = 5500 {cm}^{3} \\ \\ \implies weight \: of \: pipe = 5500 \times 2.5 = 13750 \: gm$