Math, asked by sumit8332, 11 months ago

The outer radius of a 3.5 metre long iron pipe is 3 cm and the inner radius is 2 CM if the weight of 1 cm ³ of iron is 2.5 gram find the weight of the iron pipe.​

Answers

Answered by BrainlyConqueror0901
37

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\therefore{\text{Weight\:of\:pipe=13750gm=13.75\:kg}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green {\underline \bold{Given : }} \\  :  \implies  \text{Length = 3.5 \: m} \\   \\   : \implies   \text{Outer \: radius}(r_{1}) = 3 \: cm \\  \\     : \implies   \text{Inner \: radius}(r_{2}) = 2 \: cm \\  \\  : \implies 1 {cm}^{3}  = 2.5 \: gm\\ \\   \red{\underline \bold{To \: Find : }}  \\  :  \implies  \text{Weight \: of \: pipe = ?}

• According to given question :

 \bold{For \: volume \: of \: pipe :  } \\   : \implies  \text{Volume \: of \: cylindrical \: pipe =} \pi \: h( { r_{1} }^{2}  -  r_{2}^{2} )  \\  \\   : \implies Volume =  \frac{22}{7}  \times 350 \times ( {3}^{2}  -   {2}^{2} ) \\  \\  :  \implies Volume =  \frac{22}{7}  \times 350 \times (9 - 4) \\  \\   : \implies Volume = 22 \times 50 \times 5 \\  \\  \green{ :  \implies  \text{Volume = 5500 \: } {cm}^{3} } \\ \\    \bold{For \: weight \: of \: pipe }  \\   : \implies  \text{Weight \: of \: pipe }= 5500 \times 2.5 \\  \\    \green{ : \implies   \text{ \red{W}\blue{e}\green{i}\purple{g}\orange{h}\pink{t}  \: of \: pipe = 13750} \: gm}

Answered by Anonymous
12

Answer:

weight of pipe = 13750 gm

Step-by-step explanation:

\implies volume \: of \: pipe = \pi \: h( {r1}^{2} -  {r2}^{2}  ) \\  \\ \implies volume \: of \: pipe =  \frac{22}{7}  \times 350 \times ( {3}^{2}  -  {2}^{2} ) \\  \\ \implies volume = 22 \times 50 \times 5 \\  \\\implies  volume = 5500 {cm}^{3}  \\  \\ \implies weight \: of \: pipe = 5500 \times 2.5  = 13750 \: gm

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