Question

the outer radius of a spherical container is 7 cm and the thickness of the container is 3cm .find the vo​

Answer 1

Correct Question :-

The outer radius of a spherical container is 7 cm and the thickness of the container is 3 cm. Find the volume.

Given :-

▪ The outer radius, R of the spherical container is 7 cm and the thickness is 3 cm. So the inner radius, r will be (7-3) = 4 cm

To Find :-

▪ Volume of the container.

Solution :-

Since, there are outer and inner radius while there is also the thickness. So it would form a ring whose volume can be calculated as,

⇒ 4/3 π { (Outer radius)³ - (Inner radius)³ }

⇒ 4/3 × 22/7 × { (7)³ - (4)³ }

⇒ 4/3 × 22/7 × (343 - 64)

⇒ 4/3 × 22/7 × 279

⇒ 4 × 22/7 × 93

⇒ 4 × 22 × 13.28

⇒ 1168.64 cm³

Hence, The volume of the spherical container is 1168.64 cm³.

Answer 2

Step-by-step explanation:

Correct Question :-

• The outer radius of a spherical container is 7 cm and the thickness of the container is 3 cm. Find the volume of the metal contained in the shell.

Given :-

• The outer radius, R of the spherical container is 7 cm .

• the thickness is 3 cm.

To Find :-

• Find the volume of the metal contained in the shell.

Solution :-

we know that :

= 4/3 π { (Outer radius)³ - (Inner radius)³ }

= 4/3 × 22/7 × { (7)³ - (4)³ }

= 4/3 × 22/7 × 279

= 1168.64 cm³

Hence, the volume of the metal contained in the shell is 1168.64 cm³

More information : -

Radius :

• Radius is a line from the center to the outside of a circle or sphere. .

• The definition of a radius is a circular limit or a boundary of a specific distance which is drawn from a specific point.

Volume :

• The volume of an object is a measure of the amount of space occupied by that object, not to be confused with mass.

• The word volume implies a three-dimensional context where, by convention.

• the length is the longest distance between the object's extremities.