Question

The outermost electronic configuration of an element is 3S² 3P⁵ a) write the complete subshell electronic configuration b)Find the atomic number of the element C) write the subshell electronic configuration using symbol of nearest noble gas​

Answer 1

a) 1s2 2s2 2p6 3s2 3p5
b) 17
c) [Ne] 3s2 3p5

Hope it helped

Answer 2

Answer:

a) The element's complete subshell electronic configuration is $1s^{2}2s^{2}2p^{6} 3s^{2}3p^{5}$.

b) The element's atomic number is $17$.

c) The element of an atomic number $17$ having subshell's electronic configuration using the symbol of nearest noble gas​ is $[Ne] 3s^{2}3p^{5}$.

Explanation:

Given,

The electronic configuration of an element = $3s^{2} 3p^{5}$

a)  The complete subshell electronic configuration:

As we know,

• According to the Aufbau Principle, the order follows:

$1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7p$

Therefore,

• The complete subshell electronic configuration is $1s^{2}2s^{2}2p^{6} 3s^{2}3p^{5}$

b) The atomic number of the element:

From the above configuration, $1s^{2}2s^{2}2p^{6} 3s^{2}3p^{5}$, the total electrons present are:

• $2 + 2+ 6+2+5$ = $17$

Therefore,

• The atomic number of the element is $17$

c) The subshell's electronic configuration using the symbol of nearest noble gas​:

From the above configuration, $1s^{2}2s^{2}2p^{6} 3s^{2}3p^{5}$, we can say that the nearest noble gas is neon of atomic number $10$.

Now,

• The configuration of the neon is $1s^{2}2s^{2}2p^{6}$

Therefore, in terms of noble gas configuration;

• The subshell's electronic configuration of the element of atomic number $17$ is $[Ne] 3s^{2}3p^{5}$.