Question

The output of a step-down transformer is measured to be
24 V when connected to a 12 W light bulb. The value of the
peak current is
(a) 1 / √2 A (b) √2 A
(c) 2 A (d) 2 √2 A

Answer 1

Answer:

a) 1 / √2 A

Explanation:

Output of the step down transformer = Es =24v  (Given)

Output after connecting with a light bulb = Ps = 12w  (Given)

Now,

Is = Ps/Es

= 12/24

= 1/2A

Io = √2Is

= √2×1/2

= 1/√2 A

Thus, the value of peak current is = 1/√2 (A)