The output of a step-down transformer is measured to be 24 V when connected to a 12 W light bulb. The value of the peak current is(a) 1/√2 A(b) √2 A(c) 2 A(d) 2√2 A
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d) 2√2 A
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Answer:
A) 1/√2 A
Explanation:
Output of the step down transformer = Es =24v (Given)
Output after connecting with a light bulb = Ps = 12w (Given)
Now,
Is = Ps/Es
= 12/24
= 1/2A
Io = √2Is
= √2×1/2
= 1/√2 A
Thus, the value of peak current is - 1/√2 A
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