the overall percentage of failures in a certain examination is 40 what is the probability that out of a group of 6 candidate at least for pass the examination ?
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Explanation:
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6
p(passed) = .6
p(failed) = .4
Binomial distribution
for example for 4 of 6 passed
C(6,4) .6^4 .4^2
C(6,4) = 6!/[ 4!(2!)] = 6*5/2 = 15
15 * .6^4*.4^2 = .311
do that also for 6,5
and for 6,6
and add those three results
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