Question

The overbridge at a road junction rises 1.5 m every 40 m on the horizontal level.The height of the overbridge at the highest level is 9 m. It is at the highest level for 40 m. Then the bridge slopes down at the same rate. What is the length of the horizontal road on the ground covered by the bridge from the beginning to the end?

Answer 1

Highest hight of bridge = 9m

let the length of bridge be X

according to question

since the change in hight is 6 times the the highest hight so horizontal hight = 6*40= 240m

using paythegors theorem

240^2 - 9^2 = side of road

side of road = 239.83

so total length = 2*239.83=478.6 6

Answer 2

ANSWER

Highest height of the bridge = 9m.

Let us take the length be x.

A/Q,

6 × Highest height = Change in height.

So, Horizontal height = 6*40 = 240m.

Now Using Pythagoras theorem, we get

Side of road^2 = 240^2 - 9^2

= 239.83

Therefore, total length = 2 × 239.83

= 478.66 m.